Find the derivative of y = sin(2x(^3) + 3x – 4)
- A.
cos (2x^{3} + 3x – 4) - B.
-cos (2x^{3} + 3x – 4) - C.
(6x^{2} + 3) cos (2x^{3} + 3x – 4) - D.
-(6x^{2} + 3) cos (2x^{3} + 3x – 4)
Correct Answer: Option C
Explanation
y = sin (2x(^3) + 3x – 4)
let u = 2x(^3) + 3x – 4
∴du/dx = 6x(^2)
y = sin u
dy/du = cos u
dy/dx = du/dx * dy/du
∴dy/dx = (6x(^2) + 3) cos u
= (6x(^2) + 3)cos(2x(^3) + 3x – 4)